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为了帮忙解决朋友的问题，真琴不断以同样的方法回到过去。她突然发现自己手臂上的数字原来是穿越时空的次数，次数变得越来越少，与此同时她也发现了千昭的秘密……罗力亚（郑嘉颖 饰）为王思苦（胡杏儿 饰）而犯法入狱，思苦受力亚启发放弃名利，肩负起为弱势社群争取法律公义的使命。思苦为街坊讨回公道，不惜放下身段跑到街头上抗争，因而赢得“女Law霸”的称号。而出狱後的力亚欣然当一个地踎师爷，成为思苦背後的男人，两人双剑合壁成了深水埗的“神雕侠侣”，继续为民请命，但力亚与思苦的处事态度和方法往往截然不同，因而产生不少磨擦。而力亚的前妻景伶俐（苟芸慧 饰）突然从美国归来，令力亚与思苦的感情备受考验。此际，他们因处理塌楼意外案件而惹来地产富商不满，令力亚招致杀身之祸。死党丁家富（李璨琛 饰）与米佐冶（林子善 饰），以及新落区的杂差梁包升（曹永廉 饰）同受牵连，最终他们能否合力以法律彰显公义，为弱势市民讨回公道？我们保持密切联系时所看到的是令人惊叹的人类戏剧。In addition to solving the port problem of A, the serial number problem also needs to be paid attention to. The serial number corresponds to the sliding window. The fake TCP packet needs to be filled with the serial number. If the value of the serial number is not in the sliding window of B when it is sent to B before A, B will actively discard it. So we need to find the serial number that can fall into the sliding window between AB at that time. This can be solved violently, because the length of a sequence is 32 bits, and the value range is 0-4294967296. If the window size is like 65535 under Windows I caught in the above figure, I only need to divide, and I know that at most I only need to send 65537 (4294967296/65535=65537) packets to have a sequence number fall into the sliding window. The desired value can be calculated quickly by exhaustion on multiple control hosts.《整容的诱惑》为单集剧，共16集，每集一个独立的整容故事，整部剧节奏轻快而温馨，劲爆而不低俗地展现了不同整容者和整容医生背后的故事和心态，而剧中的实习整容医生李美丽在经历了一系列的整容案例后也实现了自我情感和事业上的成长，给观众传递去人类最本真的情感与正能量。在《梦宅》这部影片中，丹尼尔·克雷格扮演的主人公带着全家搬进了一个理想中的小镇，住进了一幢完美的房子，然而很快他就发现这幢房子的前任主人被人谋杀死在这里并且阴魂不散。